Optimal. Leaf size=105 \[ -\frac{(a C+b B) \sin ^3(c+d x)}{3 d}+\frac{(a C+b B) \sin (c+d x)}{d}+\frac{(3 a B+4 b C) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{1}{8} x (3 a B+4 b C)+\frac{a B \sin (c+d x) \cos ^3(c+d x)}{4 d} \]
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Rubi [A] time = 0.177823, antiderivative size = 105, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 38, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.158, Rules used = {4072, 3996, 3787, 2633, 2635, 8} \[ -\frac{(a C+b B) \sin ^3(c+d x)}{3 d}+\frac{(a C+b B) \sin (c+d x)}{d}+\frac{(3 a B+4 b C) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{1}{8} x (3 a B+4 b C)+\frac{a B \sin (c+d x) \cos ^3(c+d x)}{4 d} \]
Antiderivative was successfully verified.
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Rule 4072
Rule 3996
Rule 3787
Rule 2633
Rule 2635
Rule 8
Rubi steps
\begin{align*} \int \cos ^5(c+d x) (a+b \sec (c+d x)) \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx &=\int \cos ^4(c+d x) (a+b \sec (c+d x)) (B+C \sec (c+d x)) \, dx\\ &=\frac{a B \cos ^3(c+d x) \sin (c+d x)}{4 d}-\frac{1}{4} \int \cos ^3(c+d x) (-4 (b B+a C)-(3 a B+4 b C) \sec (c+d x)) \, dx\\ &=\frac{a B \cos ^3(c+d x) \sin (c+d x)}{4 d}-(-b B-a C) \int \cos ^3(c+d x) \, dx-\frac{1}{4} (-3 a B-4 b C) \int \cos ^2(c+d x) \, dx\\ &=\frac{(3 a B+4 b C) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a B \cos ^3(c+d x) \sin (c+d x)}{4 d}-\frac{1}{8} (-3 a B-4 b C) \int 1 \, dx-\frac{(b B+a C) \operatorname{Subst}\left (\int \left (1-x^2\right ) \, dx,x,-\sin (c+d x)\right )}{d}\\ &=\frac{1}{8} (3 a B+4 b C) x+\frac{(b B+a C) \sin (c+d x)}{d}+\frac{(3 a B+4 b C) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a B \cos ^3(c+d x) \sin (c+d x)}{4 d}-\frac{(b B+a C) \sin ^3(c+d x)}{3 d}\\ \end{align*}
Mathematica [A] time = 0.274893, size = 91, normalized size = 0.87 \[ \frac{-32 (a C+b B) \sin ^3(c+d x)+96 (a C+b B) \sin (c+d x)+24 (a B+b C) \sin (2 (c+d x))+3 a B \sin (4 (c+d x))+36 a B c+36 a B d x+48 b c C+48 b C d x}{96 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.069, size = 107, normalized size = 1. \begin{align*}{\frac{1}{d} \left ( Ba \left ({\frac{\sin \left ( dx+c \right ) }{4} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+{\frac{3\,\cos \left ( dx+c \right ) }{2}} \right ) }+{\frac{3\,dx}{8}}+{\frac{3\,c}{8}} \right ) +{\frac{Bb \left ( 2+ \left ( \cos \left ( dx+c \right ) \right ) ^{2} \right ) \sin \left ( dx+c \right ) }{3}}+{\frac{aC \left ( 2+ \left ( \cos \left ( dx+c \right ) \right ) ^{2} \right ) \sin \left ( dx+c \right ) }{3}}+Cb \left ({\frac{\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{2}}+{\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.982585, size = 136, normalized size = 1.3 \begin{align*} \frac{3 \,{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} B a - 32 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} C a - 32 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} B b + 24 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} C b}{96 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.495079, size = 205, normalized size = 1.95 \begin{align*} \frac{3 \,{\left (3 \, B a + 4 \, C b\right )} d x +{\left (6 \, B a \cos \left (d x + c\right )^{3} + 8 \,{\left (C a + B b\right )} \cos \left (d x + c\right )^{2} + 16 \, C a + 16 \, B b + 3 \,{\left (3 \, B a + 4 \, C b\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{24 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.18547, size = 367, normalized size = 3.5 \begin{align*} \frac{3 \,{\left (3 \, B a + 4 \, C b\right )}{\left (d x + c\right )} - \frac{2 \,{\left (15 \, B a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - 24 \, C a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - 24 \, B b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 12 \, C b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - 9 \, B a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 40 \, C a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 40 \, B b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 12 \, C b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 9 \, B a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 40 \, C a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 40 \, B b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 12 \, C b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 15 \, B a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 24 \, C a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 24 \, B b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 12 \, C b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )}^{4}}}{24 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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